[no subject]

The only problem there is I know how to do this in C.  Uoi can do it in
perl but I have no clue how to in bash.

You might be able to do something like this:

LOCATION=`perl <<EOF
......
EOF
`

Then check the value of that variable.

Or maybe this will work in bash

[cfowler at cfowler cfowler]$ FD1=`ls -l /proc/$$/fd/1 | cut -d '>' -f2`;
[cfowler at cfowler cfowler]$ echo $FD1
/dev/pts/1

You'll want to check FD1 for the word cron.  


On Mon, 2005-06-27 at 00:17, Christopher Bergeron wrote:
> Does anyone know of an easy way for my script to determine if it's being 
> run from cron or from a user shell? 
> 
> I have a feeling theres an easy way to do this, but I'm drawing a 
> complete blank right now.  I'm looking at my Environment vars, but I'm 
> not sure what gets set by Cron when it runs a script.
> 
> Any ideas are much appreciated...
> 
> Kind regards,
> CB
> 
> 
> _______________________________________________
> Ale mailing list
> Ale at ale.org
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</pre>
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<li><strong><a name="00785" href="msg00785.html">[ale] Bash:  How to determine if called from cron?</a></strong>
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