[no subject]

Then I saw Geoffrey's solution and decided it was _MUCH_ faster and way
less typing!

When Fletch chimes in with his one liner that takes me longer to
understand than type with one finger, I will be completely humbled.

Learning new stuff every day....

On Wed, 2004-05-12 at 19:56, Jonathan Glass wrote:
> I'm trying to parse a printer log file.  Here is a snippet of a single
> print job (I added the extra lines for legibility):
> -----------
> jobstart '-HMUTT' '-nomard' '-Plp' '-kcfA008MUTT' '-b752686'
> '-t2003-02-18-16:15:53.000'
> 
> start '-q29645' '-p241810' '-t2003-02-18-16:15:55.087' '-Aomard at MUTT+8'
> '-nomard' '-Plp'
> 
> filestart '-q29646' '-p241810' '-t2003-02-18-16:15:57.095'
> '-Aomard at MUTT+8' '-nomard' '-Plp'
> 
> fileend '-b9' '-T36' '-q29646' '-p241819' '-t2003-02-18-16:16:31.076'
> '-Aomard at MUTT+8' '-nomard' '-Plp'
> 
> end '-b9' '-T42' '-q29645' '-p241819' '-t2003-02-18-16:16:35.070'
> '-Aomard at MUTT+8' '-nomard' '-Plp'
> 
> jobend '-HMUTT' '-nomard' '-Plp' '-kcfA008MUTT' '-b752686'
> '-t2003-02-18-16:16:35.000'
> 
> -----------------
> 
> All I need to do is pull out the user (-nomard, -name omard) and the
> number of pages printed (fileend -p241819, subtract filestart -p241810).
> 
> I can think of ways of pulling a single variable out (username, #pages
> at start, #pages at end), but can't figure out how to pull out all 3
> simultaneously.
> 
> i'm hoping to parse through the past year's worth of logs and create a
> cumulative total, broken down by user and month.
> 
> I recently saw a perl regex that could do this, but it was too complex
> for me to follow.
> 
> Any suggestions, pointers, tips?  I really need this report fairly soon,
> unfortunately.
> 
> TIA
> 
> Jonathan Glass
> 
> _______________________________________________
> Ale mailing list
> Ale at ale.org
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</pre>
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