[ale] C Programming Question

[eric.ayers at mindspring.com (Eric Z. Ayers)]

JB Wells wrote:
> 
> I think this will work:
> 
> char **a=(char **)malloc (sizeof(char **));

^^ You need to change this line:
char **a=(char **)malloc (sizeof(char **) * WHATEVER);

> 
> for (i=0; i<WHATEVER; i++)
> {
>     /* if the pointer will be pointing to a string,
>        you should change it to
>        (char *)malloc(sizeof(char) * strlen(STRING))*/
> 
>     a[i]=(char *)malloc(sizeof(char *));
> }
> 
> =====
> --------------------------
> John B. Wells IV
> Application Developer
> Acterna
> 6100 Lake Forrest Drive
> Atlanta, GA  30328
> 404.531.8938
> 
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