[ale] C Programming Question

[jbwellsiv at yahoo.com (JB Wells)]

I think this will work:

char **a=(char **)malloc (sizeof(char **));

for (i=0; i<WHATEVER; i++)
{
    /* if the pointer will be pointing to a string,
       you should change it to 
       (char *)malloc(sizeof(char) * strlen(STRING))*/

    a[i]=(char *)malloc(sizeof(char *));
}

=====
--------------------------
John B. Wells IV
Application Developer
Acterna
6100 Lake Forrest Drive
Atlanta, GA  30328
404.531.8938

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